tee command doubt

How to use tee such that the list of the logged users as well as their count is displayed only on the terminal and the same is not stored in any file.

who |tee <0; who |wc -l
this ll work.....

"tee" command sends the output to standard output and also to a file.

eg

Code:

$ ls | tee -a -i sample.txt

Output of ls command will be printed in the screen and also stored in sample.txt file.

-a ---> append to the file
-i ---> ignore interrupts

<0 is not required in above command.

This can also be used
who -q | tee

This command will save the result in some temporary file and also display the result.

what is the use of '-q' option?

i got it. It is called quick who. Only displays logged in usernames and their count...

-q is used for displaying only logged users name and total no. of users logged on.

even "who -q" produces the same output. then wat is the significance of using "tee" command there.

since the question needs it...............maybe

k k

Main purpose of tee command is to split the output and write it to both a file and stdout
The solution that i think is,
just write the command without 'tee' which serves the purpose
and append ' | tee ' to it. simple

Here are some of the ways to do it,
( who ; who | wc -l ) | tee
(who | tee ) ; (who | wc -l) | tee

However the outlet to file in ' T ' should be made dummy...